$K^{+}, C l^{-}, C a^{2 +}, S^{2 -}$ ions are isoelectronic. The decreasing order of their size is :

S^{2 -} > C l^{-} > K^{+} > C a^{2 +}

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C a^{2 +} > K^{+} > C l^{-} > S^{2 -}

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K^{+} > C l^{-} > C a^{2 +} > S^{2 -}

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C r > S^{2 -} > C a^{2 +} > K^{+}

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Solution

The correct option is A $S^{2 -} > C l^{-} > K^{+} > C a^{2 +}$
The decreasing order is :
$S^{2 -} > C l^{-} > K^{+} > C a^{2 +}$ . Anions are larger than cations. More the negative charge more is the size.

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Similar questions

K^{+}, C l^{-}, S^{2 -}, C a^{2 +}

The correct order of ionic size of the species $K^{+}, C l^{-}, C a^{2 +}$ and $S^{2 -}$ is:

S^{2 -}, K^{+}, C a^{2 +}, C l^{-}

K^{+}, {C l}^{-}, {C a}^{2 +}, S^{2 -}

S^{2 -}, N a^{+}, C a^{2 +}, C l^{-}

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