Question

$K_f$ of $1,4$ -dioxane is 4.9$Kkg{mol}^{-1}$ for 1000$g.$ The depression in freezing point for a $0.001m$ solution in dioxane is:

• A. 0.0049
• B. $4.9+0.001$
• C. 49
• D. 0.49

Answer 1

The correct option is A 0.0049

here,

$k_f=4.9,m=0.001$

Now,

as,

$\Delta T_F=k_f\times m$

$=4.9\times 0.001=0.0049$