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Salt of Weak Acid and Weak Base

Kh hydrolysis...

Question

$K_{h}$ (hydrolysis constant) of ammonium benzoate can be calculated by the formula:

\sqrt{\frac{K_{w}}{K_{a} C}}

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\sqrt{\frac{K_{w}}{K_{a} \times K_{b}}}

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\sqrt{\frac{K_{w}}{K_{b} \times C}}

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\sqrt{\frac{K_{h}}{C}}

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Solution

The correct option is D $\sqrt{\frac{K_{w}}{K_{a} \times K_{b}}}$
The salt Ammonium Benzoate is formed from a weak acid, Benzoic acid, and weak base, ammonium hydroxide.
The degree of hydrolysis is calculated from
$K_{h} = \sqrt{\frac{K_{w}}{K_{a} \times K_{b}}}$
$K_{w} =$ Ionic product of water
$K_{a} =$ Dissociation constant of acid.
$K_{b} =$ Dissociation constant of base.

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