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Byju's Answer
Standard XII
Chemistry
Ideal Gas Equation
K p for the r...
Question
K
p
for the reaction
A
(
g
)
+
B
(
g
)
⇌
2
C
(
g
)
;
is
0.5
at
T
=
295
K
.
If initially
P
A
=
1
a
t
m
,
P
B
=
10
a
t
m
and
P
c
=
5
a
t
m
,
then:
A
△
G
<
0
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B
△
U
=
T
△
S
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C
△
G
0
=
0
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D
△
G
>
0
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Solution
The correct option is
B
△
G
>
0
A
(
g
)
+
B
(
g
)
⇌
2
c
(
g
)
Initial
(
P
)
1
a
t
m
10
a
t
m
5
a
t
m
Let
Q
p
be the reaction quotient initially
∴
Q
p
=
(
5
)
2
1
×
10
=
25
10
=
2.5
&
K
p
=
0.5
Here,
K
p
<
Q
p
∴
The value of
Q
p
will tend to decreases to reach the value of
K
p
& the reaction will proceed in reverse direction
∴
△
G
>
0
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0
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Q.
L
e
t
g
(
x
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=
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x
0
f
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t
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d
t
,
f
i
s
s
u
c
h
t
h
a
t
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2
≤
f
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t
)
≤
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f
o
r
t
ϵ
[
0
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]
a
n
d
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≤
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(
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)
≤
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o
r
t
ϵ
[
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,
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]
.
T
h
e
n
g
(
2
)
s
a
t
i
s
f
i
e
s
t
h
e
i
n
e
q
u
a
l
i
t
y
Q.
Let
f
(
x
)
=
⎧
⎨
⎩
g
(
x
)
.
cos
1
x
if
x
≠
0
0
if
x
=
0
where
g
(
x
)
is an even function differentiable at
x
=
0
, passing through the origin. Then
f
′
(
0
)
Q.
Calculate
K
p
for the reaction
A
(
g
)
⇌
B
(
g
)
+
2
C
(
g
)
at
305
K
.
K
c
=
0.2
Q.
If
f
:
R
→
R
,
f
(
x
)
=
⎧
⎨
⎩
1
x
>
0
0
x
=
0
−
1
x
<
0
and
g
:
R
→
R
,
g
(
x
)
=
[
x
]
, then
(
f
∘
g
)
(
π
)
is:
Q.
For a reaction
A
(
g
)
⇌
B
(
g
)
, if initial pressure at
300
o
C
is 1 atm and its
K
p
is 4,. Then calculate
P
B
at equilibrium state.
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