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Le Chatelier's Principle

Kp for the re...

Question

$K_{p}$ for the reaction $A ⇌ B$ is 4. If initially only A is present then what will be the partial pressure of B after equilibrium?

1.2

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0.8

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0.6

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Solution

The correct option is B 0.8
For given reaction,
$K_{p} = K_{c}$
Assuming that reaction is started with 1 mole of A and at equilibrium x moles of A have reacted,

$K_{p} = \frac{P_{B}}{P_{A}} = 4$
$\frac{x}{1 - x} = 4$
$5 x = 4 x = 0.8$

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