$K_{p}$ for the reaction $C u S O_{4} .3 H_{2} O_{(s)} + 2 H_{2} O_{(g)} \to C u S O_{4} . 5 H_{2} O_{(s)} i s 1.0 \times 10^{4} a t m^{- 2}$ at certain temperature. What lowest relative humidity of air can be achieved using $C u S O_{4} .3 H_{2} O$ as drying agent at that temperature ? Aqueous tension at the given temperature = 16 torr

20%

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30%

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47.5%

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50%

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Solution

The correct option is C
47.5%

$K_{p} = 1.0 \times 10^{4} = \frac{1}{p_{H_{2} O}^{2}}$
$\Rightarrow p H_{2} O = 1.0 \times 10^{- 2} a t m = 760 \times 1.0 \times 10^{- 2} = 7.6 t o r r$
Relative humidity of air that can be achieved
$= \frac{7.6}{16} \times 100 = 47.5 %$

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Similar questions

C u {S O}_{4} .5 H_{2} O

C u {S O}_{4} .3 H_{2} O

C u {S O}_{4} .5 H_{2} O (s) ⇌ C u {S O}_{4} .3 H_{2} O (s) + 2 H_{2} O (v)

K_{P} = 1.086 \times 10^{- 4} {a t m}^{2}

C u S O_{4}

\cdot

5 H_{2} O (s)

⇌

C u S O_{4} \cdot

H_{2} O (s)

2 H_{2} O (g)

K_{p}

\times 10^{- 4}

a t m^{2}

27^{o} C

Select the correct relation of $K_{P}$ and $K_{C}$ for $C u {S O}_{4} .5 H_{2} O (S) ⇌ C u {S O}_{4} .3 H_{2} O (S) + 2 H_{2} O (g)$ .

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