Kp is related to Kc as Kp-Kc RT- n-

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Thermal Expansion

Kp is related...

Question

$K_{p}$ is related to $K_{c}$ as $K_{p} = K_{c} (R T)^{Δ n}$ .

True

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False

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Solution

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Similar questions

K_{p}

K_{c}

K_{p} = K_{c} (R T)^{Δ n}

K_{p}

K_{c}

K_{p}

K_{c}

K_{p} = K_{c} (R T)^{Δ n}

K_{p} = (a t m)^{Δ n}

K_{c} = (m o l L^{- 1})^{Δ n}

C O (g) + H_{2} O (g) ⇌ C O_{2} (g) + H_{2} (g); K_{1}

C H_{4} (g) + 2 H_{2} O (g) ⇌ C O_{2} (g) + 4 H_{2} (g); K_{2}

C H_{4} (g) + C O + 3 H_{2} O (g) ⇌ 2 C O_{2} (g) + 5 H_{2} (g); K_{3}

The relation between equilibrium constant $K_{P}$ and $K_{C}$ is

K_{c}

K_{p}

K_{p} = K_{c} (R T)^{Δ n}

Δ n

N H_{4} C l (s) ⇋ N H_{3} (g) + H C l (g)

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