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Question

KspMg(OH)2 is 4.0×1012. The number of moles of Mg2+ ions in one litre of its saturated solution in 0.1 M NaOH is :


A

4.0×1010

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B

1.0×104

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C

2.0×106

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D

8.0×106

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Solution

The correct option is A

4.0×1010


[OH]=[OH]NaOH+[OH]Mg(OH)2=0.1+2s0.1M(2X<<0.1)Ksp[Mg(OH)2]=[Mg2+][OH]2=[Mg2+]×0.12=4.0×1012[Mg2+]=4.0×1012M


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