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Question

Ksp of CdS=8×1027, Ksp of ZnS=1×1021, Ka of H2S=1×1021.
When ZnS starts precipitating, what concentration of Cd2+ is left?

A
8×107 M
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B
0.1 M
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C
4×1010 M
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D
2×109 M
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Solution

The correct option is A 8×107 M
Ksp of ZnS=1021=[Zn2+][S2]=0.1×[S2]
so [S2]=1020
now for CdS
[Ksp of CdS=8×1027=[Cd2+][S2]=[Cd2+]×1020
so [Cd2+] left = 8×107M

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