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Question

KspofMg(OH)2 is 1×1012,0.01MMgCl2 will be precipitating at the limiting pH :

A
8
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B
9
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C
10
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D
12
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Solution

The correct option is A 9
According to given data, [OH] needed for precipitation of Mg(OH)2=(1012102)1/2=(1010)1/2M=105M

pOH=log[OH]=5

So, pH=14pOH=9

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