Kspof MgOH2 is 1- 10-12- 0-01 M MgCl2 will be precipitating at the limiting pH -

The correct option is A 9According to given data, #160; [OH^ ] needed for precipitation of #160; Mg(OH)_2=( 10 ^ 12 10 ^ 2)^1/2 =( 10 ^ 10)^1/ ...

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Common Ion Effect

Kspof MgOH2 ...

Question

$K_{s p}$ of $M g (O H)_{2}$ is $1 \times 10^{- 12}, 0.01 M M g C l_{2}$ will be precipitating at the limiting pH :

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Similar questions

K_{s p}

M g {(O H)}_{2}

1 \times 10^{- 12}

0.10 M

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1 \times 10^{- 12}

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1 \times 10^{- 12}, 0.01 M M g C l_{2}

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1.2 \times 10^{- 5} m o l / L

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0.01

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