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Question

Ksp of Ze3(PO4)4 in terms of solubility (S) is:

A
108 S7
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B
4 S3
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C
6912 S7
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D
none of these
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Solution

The correct option is C 6912 S7
Here, [Zr4+] =3S and [PO34] =4S
Ksp=(3S)3(4S)4 =6912(S)7.
The correct option is C.

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