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Byju's Answer
Standard XII
Chemistry
Solubility Product
Ksp of Ze3P...
Question
K
s
p
of
Z
e
3
(
P
O
4
)
4
in terms of solubility
(
S
)
is:
A
108
S
7
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B
4
S
3
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C
6912
S
7
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D
none of these
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Solution
The correct option is
C
6912
S
7
Here,
[
Z
r
4
+
]
=
3
S
and
[
P
O
3
−
4
]
=
4
S
K
s
p
=
(
3
S
)
3
(
4
S
)
4
=
6912
(
S
)
7
.
The correct option is
C
.
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