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Question

Ksp of Zr3(PO4)4 in terms of solubility (s) is:

A
108 s7
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B
4s3
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C
6912 s7
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D
27 s4
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Solution

The correct option is C 6912 s7
Zr3(PO4)43Zr4++4PO433s4sKsp=(Zr4+)3(PO34)4Ksp=(3s)3(4s)4Ksp=27s3×256s4Ksp=6912 s7

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