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Question

Kamal and Anand each lent the same sum of money for 2 years at 5% at simple interest and compound interest respectively. Anand received Rs. 15 more than Kamal. Find the amount of money lent by each and the interest received.

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Solution

Let the principal amount be P

Interest received by Kamal is = S.I=P×r×t100SI=P(5)(2)100SI=P10=0.1P

Interest received by Anand is =

C.I=P[(1+r100)n1]CI=P[(1+5100)21]CI=P[(1.05)21]CI=P[0.1025]=0.1025P

As the difference between their interests is 15,

we get

CI - SI = 15

Putting values, we get

0.1025P0.1P=150.0025P=152510000P=15P=6000So, SI=0.1P=6000(0.1)=600And CI=600+15=615

Therefore, Kamal received 600 interest, Anand received 615; both on the principal of 6000


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