Karan can take a maximum of four shots at an enemy moving away from him. The probability of hitting the enemy at the first, second, third and fourth shots are 0.3, 0.4, 0.2 and 0.1 respectively. What is the probability that the enemy is hit when all the four shots are fired?

0.6976

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0.6864

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0.3024

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None of these

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Solution

The correct option is A
0.6976

Required Probability = 0.3 + (0.7 $\times$ 0.4) + (0.7 $\times$ 0.6 $\times$ 0.2) + (0.7 $\times$ 0.6 $\times$ 0.8 $\times$ 0.1) = 0.6976

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Karan can take a maximum of four shots at an enemy moving away from him. The probability of hitting the enemy at the first, second, third and fourth shots are 0.3, 0.4, 0.2 and 0.1 respectively. What is the probability that the enemy is hit when all the four shots are fired?

The correct option is A 0.6976 Required Probability = 0.3 + (0.7×0.4) + (0.7×0.6×0.2) + (0.7×0.6×0.8×0.1) = 0.6976

The correct option is A
0.6976

Required Probability = 0.3 + (0.7 $\times$ 0.4) + (0.7 $\times$ 0.6 $\times$ 0.2) + (0.7 $\times$ 0.6 $\times$ 0.8 $\times$ 0.1) = 0.6976