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Question

Karthik is carrying out a reaction with chemicals A and B according to the reaction, (3AB). He wants to find the order of the reaction by changing concentration of A and observing the rate of the reaction. The first observation he made was by increasing the concentration of A 4 times after which, the rate of reaction doubled. Can you guess the order of reaction using Karthik’s experimental observation?

A
1
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B
0.5
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C
1.5
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D
2
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Solution

The correct option is B 0.5
As we know, Rate Equation Rate=k[Reactant]n. where n is the order of the reaction.

Before Karthik changed the concentration, lets say concentration of reactant is a and rate of reaction is r1.

As Karthik increased the concentration by 4 times, now the concentration is 4a and by his observation we know that rate is doubled, so now the rate is 2r1.

Substituting these in Rate equation. Before concetration change rate equation is
r1=[a]n ….(1)
After concentration change rate equation is
2r1=[4a]n ….(2)
Dividing Equation (2) with Equation (1)
2r1r1=[4aa]n2=[4]n.n=12=0.5
So order of the reaction = 0.5.

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