$K B r$ , on reaction with conc. $H_{2} S O_{4}$ , gives reddish-brown gas which is:

bromine

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mixture of bromine and

H B r

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H B r

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N O_{2}

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Solution

The correct option is A bromine
Option (A) is correct.
$K B r$ , on reaction with $c o n c . H_{2} S O_{4}$ , gives reddish-brown bromine gas.
$K B r + H_{2} S O_{4} ⟶ K H S O_{4} + H B r$ , $2 H B r + H_{2} S O_{4} ⟶ B r_{2} + 2 H_{2} O + S O_{2}$

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