You visited us 6 times! Enjoying our articles? Unlock Full Access!

Copper II Sulphate

KBr, on react...

Question

$K B r$ , on reaction with conc. $H_{2} S O_{4}$ , gives reddish-brown gas which is:

bromine

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

mixture of bromine and

H B r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H B r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A bromine
Option (A) is correct.
$K B r$ , on reaction with $c o n c . H_{2} S O_{4}$ , gives reddish-brown bromine gas.
$K B r + H_{2} S O_{4} ⟶ K H S O_{4} + H B r$ , $2 H B r + H_{2} S O_{4} ⟶ B r_{2} + 2 H_{2} O + S O_{2}$

Suggest Corrections

Similar questions

K_{2} C r_{2} O_{7}

H_{2} S O_{4}

H_{2} S O_{4}

Ethyl phenyl ether on boiling with conc. HBr gives

K M n O_{4}

^{'} A^{'}

H_{2} S O_{4}

^{'} B^{'}

^{'} A^{'}

^{'} B^{'}

H_{2} S O_{4}

Join BYJU'S Learning Program