KCIO4 may be made by means of the following series of reactions- CI2 - 2KOH - KCI - KCIO - H2O 3KCIO - 2KCI - KCIO3 4KCIO3- 3KCI4 - KCIHow much CI2 is needed to prepare 200 g KCLO4 by the above sequence-

The #10;arrangement of conditions includes; #10; #10; #10;Cl_2+2KOH→ KCl+KClO+H_2O ...... ( 1 ) #10; #10; #10;3KClO→ 2KCl+KClO_3 ...... ...

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Stoichiometry

KCIO4 may be ...

Question

$K C I O_{4}$ may be made by means of the following series of reactions:
$C I_{2} + 2 K O H \to K C I + K C I O + H_{2} O$
$3 K C I O \to 2 K C I + K C I O_{3}$
$4 K C I O_{3} \to 3 K C I_{4} + K C I$
How much $C I_{2}$ is needed to prepare $200$ g $K C L O_{4}$ by the above sequence?

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Which of the following is a combination and which is a displacement reaction ?

(a) $C l_{2} + 2 K I ⟶ 2 K C I + I_{2}$

(b) $2 K + C I_{2} ⟶ 2 K C I$

C l_{2} + 2 N a O H \to N a C l + N a C l O + H_{2} O

3 N a C l O \to 2 N a C l + N a C l O_{3}

4 N a C l O_{3} \to 3 N a C l O_{4} + N a C l

C l_{2}

106.5

N a C l O_{3}

{C l}_{2}

100

K C l O_{4}

{C l}_{2} + 2 K O H \to K C l + K C l O + H_{2} O . . . (i)

3 K C l O \to 2 K C l + K C l O_{3} . . . (i i)

4 K C l O_{3} \to 3 K C l O_{4} + K C l . . . (i i i)

N a_{2} C O_{3} S O_{2} \to (A) N a_{2} C O_{3} \to (B)

E l e m e n t a l S, Δ \to (C)_{2} (D)

P C I_{5} \to P C I_{3} + C I_{2}

N_{2} + O_{2} \to 2 N O

2 K C I O_{3} \to 2 K C I + 3 O_{2}

F e^{3 +} + S C N_{-} \to F e (S C N)^{2 +}

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