KCl crystalizes in the same type of lattice as N aCl- Given that r Na - r Cl -0-5 and r K - r Cl -0-65 Then the ratio of the side of the unit cells for KCl to that of NaCl is-A- 3-3B- 1-65C- 1-1D- 1-3

The correct option is C 1.1side of unit cell of KCl /side of unit cell of NaCl =r_K^++ r_Cl^ /r_Na^++ r_Cl^ =1.65/1.5 = 1.1 nbsp; ...

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Byju's Answer

Standard XII

Chemistry

Ionic Compounds and Radius Ratios

KCl crystaliz...

Question

$K C l$ crystalizes in the same type of lattice as $N a C l$ .
Given that $\frac{r_{N a^{+}}}{r_{C l^{-}}} = 0.5$ and $\frac{r_{K^{+}}}{r_{C l^{-}}} = 0.65$ Then the ratio of the side of the unit cells for $K C l$ to that of $N a C l$ is:

1.3

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3.3

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1.65

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1.1

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Solution

The correct option is D 1.1
$\frac{s i d e o f u n i t c e l l o f K C l}{s i d e o f u n i t c e l l o f N a C l} = \frac{r_{K^{+}} + r_{C l^{-}}}{r_{N a^{+}} + r_{C l^{-}}} = \frac{1.65}{1.5} = 1.1$

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Similar questions

K C l

crystalizes in the same type of lattice as

N a C l

.
Given that

\frac{r_{N a^{+}}}{r_{C l^{-}}} = 0.5

and

\frac{r_{K^{+}}}{r_{C l^{-}}} = 0.65

Then the ratio of the side of the unit cells for

K C l

to that of

N a C l

is:

Q. KCl crystallizes in the same type of lattice as does NaCl. Given that

\frac{r_{N a^{+}}}{r_{C l^{-}}} = 0.5

and

\frac{r_{N a^{+}}}{r_{K^{+}}} = 0.7

Find the ratio of the sides of unit cell for KCl to that for NaCl :

KCl crystallizes in the same type of lattice as does NACl. Given that $\frac{r_{N a^{+}}}{r_{C l^{-}}} = 0.55$ and $\frac{r_{K^{+}}}{r_{C l^{-}}} = 0.74$ . Calculate the ratio of the side of the unit cell for KCl to that of NaCl.

Q. KCl crystallizes in the same type of lattice as does NaCl. Given that

\frac{r_{N a +}}{r_{C l -}} = 0.50

and

\frac{r_{N a +}}{r_{K +}} = 0.70

, calculate the ratio of the side of the unit cell for KCl to that of for NaCl.

K C l

crystallises in the same type of lattice as does

N a C l

. Given that

r_{N a^{+}} / r_{C l^{-}} = 0.55

and

r_{K^{+}} / r_{C l^{-}} = 0.74

. Calculate the ratio of the side of the unit cell for

K C l

to that of

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KCl crystalizes in the same type of lattice as NaCl. Given that rNa+rCl−=0.5 and rK+rCl−=0.65 Then the ratio of the side of the unit cells for KCl to that of NaCl is:

The correct option is D 1.1side of unit cell ofKClside of unit cell ofNaCl=rK++rCl−rNa++rCl−=1.651.5=1.1

$K C l$ crystalizes in the same type of lattice as $N a C l$ .
Given that $\frac{r_{N a^{+}}}{r_{C l^{-}}} = 0.5$ and $\frac{r_{K^{+}}}{r_{C l^{-}}} = 0.65$ Then the ratio of the side of the unit cells for $K C l$ to that of $N a C l$ is:

The correct option is D 1.1
$\frac{s i d e o f u n i t c e l l o f K C l}{s i d e o f u n i t c e l l o f N a C l} = \frac{r_{K^{+}} + r_{C l^{-}}}{r_{N a^{+}} + r_{C l^{-}}} = \frac{1.65}{1.5} = 1.1$