KCl crystallizes in the same type of lattice as does NaCl.Given that radius ratio of Na by Cl is 0.5 and radius of Na by K is 0.7.

Calculate the ratios of the sides of unit cell for KCl to that for NaCl and the ratio of densities of NaCl to that for KCl.

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Solution

NaCl crystallizes in the face centered cubic unit cell such that
rNa++rCl−=a2rNa++rCl−=a2,where a is the edge length of unit cell .Now since
rNa+rCl−=rNa+rCl−=0.5,rNa+rK+=0.5,rNa+rK+=0.70.7
We will have,rNa++rCl−rCl−rNa++rCl−rCl−=1.5=1.5
rK+rCl−=rK+rNa+/0.5=0.5rNa+/rK+=0.50.7rK+rCl−=rK+rNa+/0.5=0.5rNa+/rK+=0.50.7
Hence rK++rCl−rNa++rCl−=1.20.7×11.5rK++rCl−rNa++rCl−=1.20.7×11.5
aKCl/2aNaCl/2=1.20.7×1.5=aKclaNaClaKCl/2aNaCl/2=1.20.7×1.5=aKclaNaCl=1.143=1.143
Now since ,ρ=na3[MNA]ρ=na3[MNA]
∴∴ We will have
ρNaClρKCl=(aKClaNaCl)3(MNaClMKCl)ρNaClρKCl=(aKClaNaCl)3(MNaClMKCl)
⇒(1.143)3(58.574.5)⇒(1.143)3(58.574.5)=1.172

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Q. KCl crystallizes in the same type of lattice as does NaCl. Given that

\frac{r_{N a^{+}}}{r_{C l^{-}}} = 0.5

and

\frac{r_{N a^{+}}}{r_{K^{+}}} = 0.7

Find the ratio of the sides of unit cell for KCl to that for NaCl :

Q. KCl crystallizes in the same type of lattice as does NaCl. Given that

\frac{r_{N a +}}{r_{C l -}} = 0.50

and

\frac{r_{N a +}}{r_{K +}} = 0.70

, calculate the ratio of the side of the unit cell for KCl to that of for NaCl.

KCl crystallizes in the same type of lattice as does NACl. Given that $\frac{r_{N a^{+}}}{r_{C l^{-}}} = 0.55$ and $\frac{r_{K^{+}}}{r_{C l^{-}}} = 0.74$ . Calculate the ratio of the side of the unit cell for KCl to that of NaCl.

K C l

crystallises in the same type of lattice as does

N a C l

. Given that

r_{N a^{+}} / r_{C l^{-}} = 0.55

and

r_{K^{+}} / r_{C l^{-}} = 0.74

. Calculate the ratio of the side of the unit cell for

K C l

to that of

N a C l

K C l

crystalizes in the same type of lattice as

N a C l

.
Given that

\frac{r_{N a^{+}}}{r_{C l^{-}}} = 0.5

and

\frac{r_{K^{+}}}{r_{C l^{-}}} = 0.65

Then the ratio of the side of the unit cells for

K C l

to that of

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is:

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KCl crystallizes in the same type of lattice as does NaCl.Given that ​​​​​​radius ratio of Na by Cl is 0.5 and radius of Na by K is 0.7. Calculate the ratios of the sides of unit cell for KCl to that for NaCl and the ratio of densities of NaCl to that for KCl.

KCl crystallizes in the same type of lattice as does NaCl.Given that radius ratio of Na by Cl is 0.5 and radius of Na by K is 0.7.

Calculate the ratios of the sides of unit cell for KCl to that for NaCl and the ratio of densities of NaCl to that for KCl.