Question

​KClO3 on heating decomposes to give KCl and O2 , what is the volume of O2 liberated by 0.1 mole of KCl3?

Answer 1

Dear Student,

​$$\begin{gathered} 2{\mathrm{KClO}}_3\to 2\mathrm{KCl}+3{\mathrm{O}}_2 \\ 2\mathrm{mol}\mathrm{of}{\mathrm{KClO}}_3\mathrm{gives}3\mathrm{mol}\mathrm{i}.\mathrm{e}.3\times 22.4\mathrm{L}\mathrm{of}{\mathrm{O}}_2(\mathrm{since}1\mathrm{mol}\mathrm{of}\mathrm{gas}=22.4\mathrm{L}) \\ \mathrm{So},0.1\mathrm{mol}\mathrm{of}{\mathrm{KClO}}_3\mathrm{will}\mathrm{give}\frac{3\times 22.4}{2}\times 0.1=3.36\mathrm{L}\mathrm{of}{\mathrm{O}}_2 \end{gathered}$$