Question

ke of a body is increased by $44$ % percent in the momentum?

Answer 1

Relation between kinetic energy (K) and momentum (p) is

K = p² / (2m)

K2 / K1 = (p2 / p1)^2

p2 / p1 = sqrt(K2 / K1)

(p2 / p1) - 1 = sqrt(K2 / K1) - 1

Δp / p1 = sqrt(K2 / K1) - 1

Δp = p1 × [sqrt(K2 / K1) - 1]

= 100 × [sqrt(144 / 100) - 1]

= 20

Momentum is increased by 20%