Question

Keeping the velocity of projectile constant, the angle of projection is increased from $0^o$ to ${90}^o$, then the horizontal range of the projectile

• A. goes on increasing upto ${90}^o$.
• B. decreases upto ${90}^o$.
• C. increases upto ${45}^o$ and decreases afterwards.
• D. decreases upto ${45}^o$ and increases afterwards.

Answer 1

The correct option is C increases upto ${45}^o$ and decreases afterwards.

Horizontal Range, $R=\frac{u^2\sin 2\theta }{2g}$
$R\propto \sin 2\theta$
$\sin 2\theta$ increases till $2\theta ={90}^0$
i.e $\theta ={45}^0$
Hence, Range $R$ increases till ${45}^0$ then decreases.