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Byju's Answer
Standard XII
Physics
Idea behind a PPC
Keeping the v...
Question
Keeping the voltage of charging source cons†an t, what would be the percentage change in the energy stored in a parallel plate capacitor if the separation between the plates were to be increased by 10%
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Q.
Two plates of a parallel plate capacitor carry charges q and -q are separated by a distance x from each other. The capacitor is connected to a constant voltage source
V
0
. The distance between the plates is changed to x+ dx. Then in steady state.
Q.
A parallel-plate vacuum capacitor with plate area
A
and separation
x
has charges
+
Q
and
−
Q
on its plates. The capacitor is disconnected from the source of charge, so the charge on each plate remains fixed.
The plates are pulled apart an additional distance
d
x
. What is the change in the stored energy?
Q.
In a parallel plate capacitor with air between the plates each plate has an area of 5 × 10
-3
metre square and the separation between the plates is 2.5 millimetres.
Calculate the capacitance of the capacitor .
If this capacitor is connected to 100 volt supply what would be the charge on each plate.
How would the charge on the plate be affected if a 2.5 mm thick mica sheet of K equal to 8 is inserted between the plates while the voltage supply remains connected ?
Q.
A parallel-plate vacuum capacitor with plate area
A
and separation
x
has charges
+
Q
and
−
Q
on its plates. The capacitor is disconnected from the source of charge, so the charge on each plate remains fixed.
What is the total energy stored in the capacitor?
Q.
Statement
1
:
A parallel plate capacitor is charged by a battery of voltage
V
. The battery is then disconnected. If the space between the plates is filled with a dielectric, the energy stored in the capacitor will decrease.
Statement
2
:
The capacitance of a capacitor increases due to the introduction of a dielectric between the plates.
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