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Keeping the v...

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Keeping the voltage of charging source cons†an t, what would be the percentage change in the energy stored in a parallel plate capacitor if the separation between the plates were to be increased by 10%

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Q. Two plates of a parallel plate capacitor carry charges q and -q are separated by a distance x from each other. The capacitor is connected to a constant voltage source

V_{0}

. The distance between the plates is changed to x+ dx. Then in steady state.

Q. A parallel-plate vacuum capacitor with plate area

A

x

+ Q

- Q

on its plates. The capacitor is disconnected from the source of charge, so the charge on each plate remains fixed. The plates are pulled apart an additional distance

d x

. What is the change in the stored energy?

Q. In a parallel plate capacitor with air between the plates each plate has an area of 5 × 10^-3 metre square and the separation between the plates is 2.5 millimetres.
Calculate the capacitance of the capacitor .
If this capacitor is connected to 100 volt supply what would be the charge on each plate.
How would the charge on the plate be affected if a 2.5 mm thick mica sheet of K equal to 8 is inserted between the plates while the voltage supply remains connected ?

Q. A parallel-plate vacuum capacitor with plate area

A

x

+ Q

- Q

on its plates. The capacitor is disconnected from the source of charge, so the charge on each plate remains fixed. What is the total energy stored in the capacitor?

Statement 1 :

A parallel plate capacitor is charged by a battery of voltage

V

. The battery is then disconnected. If the space between the plates is filled with a dielectric, the energy stored in the capacitor will decrease.

Statement 2 :

The capacitance of a capacitor increases due to the introduction of a dielectric between the plates.

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