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KF crystalliz...

Question

$K F$ crystallizes in the $N a C l$ type structure. If the radius of $K^{+}$ ions $132$ pm and that of $F^{-}$ ion is $135$ pm, what is the closet $K - K$ distance?

Cannot say

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534

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755

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378

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Solution

The correct option is D $378$ pm
Closest distance between k-k
$R^{+} + R^{-} = \frac{a}{2} = 132 + 135 = 267$ pm
Therefore closest distance between $k - k = \frac{a}{2} \times \sqrt 2$
$= 267 \times \sqrt 2 = 378$ pm

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