Kim has a long pole of length 2m which makes an angle of $20^{\circ}$ with vertical. Kim takes a rope of length 5m and ties it to the pole. Now Kim moves along a circle so that the angle between initial and final rope positions is $22^{\circ}$ . What is the radius and angle subtended by the arc formed by Kim’s movement?

2 m , $20^{\circ}$ .

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5 m , $20^{\circ}$

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2 m , $20^{\circ}$

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5 m, $22^{\circ}$

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Solution

The correct option is D
5 m, $22^{\circ}$

The circle formed by Kim’s movement has a radius of 5 m because Kim is at a constant distance of 5m from the centre that is the pole. The angle subtended is the angle between the initial and final positions of Kim. This is $22^{\circ}$ .

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The correct option is D 5 m, 22∘ The circle formed by Kim’s movement has a radius of 5 m because Kim is at a constant distance of 5m from the centre that is the pole. The angle subtended is the angle between the initial and final positions of Kim. This is 22∘.

The correct option is D
5 m, $22^{\circ}$

The circle formed by Kim’s movement has a radius of 5 m because Kim is at a constant distance of 5m from the centre that is the pole. The angle subtended is the angle between the initial and final positions of Kim. This is $22^{\circ}$ .