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Relating Translational KE and T

Kinetic energ...

Question

Kinetic energy of 0.3 mole of 'He' gas in a container of maximum capacity of 4 litre at 5 atm, must be :
(R= 0.0821 atm litre $m o l^{- 1} K^{- 1}$ )

30 atm litre

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100 atm litre

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9 atm litre

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11.11 atm litre

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Solution

The correct option is B 30 atm litre
$P V = \frac{1}{3} m n c^{2}$
$\frac{3}{2} P V = \frac{1}{2} m n c^{2} = K E$
$K E = \frac{3}{2} P V = \frac{3}{2} \times 5 \times 4 = 30$ atm litre

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