Kinetic energy of a body of mass $0.1 k g$ and momentum $20 k g m s^{- 1}$ is:

1 k J

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2 k J

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3 k J

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4 k J

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Solution

The correct option is C $2 k J$

Given, $p = 20 k g m s^{- 1}, m = 0.1 k g$
Kinetic energy, $K = \frac{1}{2} m v^{2}$ and momentum, $p = m v$
So, $K = \frac{1}{2} m \times {(\frac{p}{m})}^{2} = \frac{p^{2}}{2 m}$
$∴$ $K = \frac{20^{2}}{2 \times 0.1} = 2000 J = 2 k J$

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