Question

Kinetic energy of equal masses of $C{H}_4,O_2,S{O}_2$ under similar conditions will be in the ratio of?

• A. 1 : 1 : 1
• B. 1 : 2 : 3
• C. 4 : 2 : 1
• D. 1 : 2 : 4

Answer 1

The correct option is C 4 : 2 : 1

Mole= $\frac{Weight}{\text{Molecular weight}}$

Moles of methane= $\frac{mass}{16}$

Moles of oxygen= $\frac{mass}{32}$

moles of $S{O}_2=\frac{mass}{64}$

$\therefore$ Ratio between the molecules in equal mass $C{H}_4,O_2,S{O}_2$ is $4:2:1$ .