Kinetic energy of the liquid per unit mass is

\frac{1}{2} m v^{2}

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\frac{1}{2} v^{2}

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\frac{1}{2} m^{2} v

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m v^{2}

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Solution

The correct option is B $\frac{1}{2} v^{2}$
Let $m$ be the mass of liquid and $v$ be the velocity of liquid
Hence ,
Kinetic energy of liquid $, K = \frac{1}{2} m v^{2}$

$∴$ Kinetic energy of liquid per unit mass $= \frac{K}{m} = \frac{1}{2} v^{2}$

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Kinetic energy of the liquid per unit mass is

The correct option is B 12v2Let m be the mass of liquid and v be the velocity of liquid Hence ,Kinetic energy of liquid ,K=12mv2∴ Kinetic energy of liquid per unit mass =Km=12v2

The correct option is B $\frac{1}{2} v^{2}$
Let $m$ be the mass of liquid and $v$ be the velocity of liquid
Hence ,
Kinetic energy of liquid $, K = \frac{1}{2} m v^{2}$

$∴$ Kinetic energy of liquid per unit mass $= \frac{K}{m} = \frac{1}{2} v^{2}$