Question

King, queen, ace, and jack of diamonds are removed from a pack of 52 cards. The remaining cards in the pack are well shuffled. A card is drawn randomly from the remaining cards. Find the probability of getting a card of a jack.

• A. $\frac{1}{24}$
• B. $\frac{1}{12}$
• C. $\frac{1}{48}$
• D. $\frac{1}{16}$

Answer 1

The correct option is D $\frac{1}{16}$

Total no. of cards in original pack = 52
Since four cards are removed, now total number of cards left in the remaining pack = 48
Total no. of outcomes = 48
Total no. of jack in the pack of card = 4
Since one jack is removed, now total no. of jack (number of favorable outcomes) left in the remaining pack$=4-1=3$

$\text{Probability P(E)}$ = $\frac{\text{Number of outcomes favorable to E}}{\text{Number of all possible outcomes of the experiment}}$
= $\frac{3}{48}$
= $\frac{1}{16}$