$K M n O_{4}$ acts as an oxidising agent in alkaline medium. When alkaline $K M n O_{4}$ is treated with KI, iodide ion is oxidised to:

I_{2}

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I O^{-}

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I O_{3}^{-}

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I O_{4}^{-}

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Solution

The correct option is C $I O_{3}^{-}$
In alkaline solution, the iodide ions are oxidised by $K M n O_{4}$ to iodates $(I O_{3}^{-})$ .

$2 K M n O_{4} + H_{2} O + K I ⟶ 2 M n O_{2} + 2 K O H + K I O_{3}$

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