wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

KMnO4 decomposes on heating according to the equation-

2KMnO4K2MnO4+MnO2+O2

On heating KMnO4, 1 litre of oxygen was collected at room temperature and it was found that the test tube had undergone a loss in mass of 1.32 g. If one litre of hydrogen under the same conditions of temperature and pressure has a mass of 0.0825 g. Calculate the relative molecular mass of oxygen.


A

16 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

8 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

32 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

24 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

32 g


Vapour density of oxygen = Weight of 1 litre of gas O2Weight of 1 litre of H2

Weight of 1 litre of oxygen = 1.32 g [since on collecting 1 litre of O2 the loss in mass is 1.32 g]

Vapour density of oxygen = 1.320.0825 = 16

Relative molecular mass of oxygen = 2 × Vapour density = 32 g.


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mass-Volume relation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon