KO2+S△→(A)BaCl2−−−−→(B)(whiteppt)Carbon−−−−→△(C)HCl−−−→D(gas) (D) gas turns lead acetate paper black. (A) to (D) are (A) :K2SO4 (B) :BaSO4 (C) :BaS (D) :H2S If true enter 1, else enter 0.
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Solution
The reactions are as shown below. KO2+S△→K2SO4(A)BaCl2−−−−→BaSO4(B)(whiteppt)Carbon−−−−→△BaS(C)HCl−−−→H2S(D, gas) H2S(D) gas turns lead acetate paper black. Thus, (A) to (D) are (A) :K2SO4 (B) :BaSO4 (C) :BaS (D) :H2S