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Introduction to E2 Mechanism

Kolbe electro...

Question

Kolbe electrolysis of potassium succinate gives $C O_{2}$ , __, _ and ___.

C_{2} H_{6}

and

K O H

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C_{2} H_{2}

and

K O H

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C_{2} H_{4}, K O H

and

H_{2}

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C H_{4}, C_{2} H_{6}

and

C_{2} H_{4}

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Solution

The correct option is D $C_{2} H_{4}, K O H$ and $H_{2}$
The Kolbe reaction is formally a decarboxylative dimerisation of two carboxylic acids (or carboxylate ions). In case of potassium succinate, both the $C O_{2}$ yields from same molecules, decarboxylation gives a radical intermediate, the two such intermediates combine to form a double bond and produce $C H_{2} = C H_{2}$ .

Hence, the correct option is $C$

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