CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Ksp of M(OH)x is 27×1012 and its solubility in water is 103 molL1. The value of x is .

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3
Ksp of M(OH)x= Xx.(S)X+1= 27×1012

By putting x=1,2,3...
We get, x=3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solubility and Solubility Product
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon