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Question

L1 is a line intersecting x and y axes at A(a,0) and B(0,b). L2 is a line perpendicular to L1 intersecting x and y axes at C and D respectiveley. If the area of the triangle OCD is 4 times the area of triangle OAB, then equation of AD is

A
x+2y=26
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B
2x+y+2a=0
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C
x2y+2b=0
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D
2xy2a=0
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Solution

The correct option is D 2xy2a=0
Equation of AB:xa+yb=1
L2L1xbya=α
xαb+yαa=1
C:(αb,0),D:(0,αa)
Ar(ΔOCD)
=12×OC×OD=12×(αb)(αa)=α22|ab|

Ar(ΔOAB)
=12×OA×OB=12|ab|
α22|ab|=4×12|ab|α=±2
A(a,0),D(0,2a)
Line passing through A and D
xa+y2a=12xy2a=0

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