Question

$‘l^{\prime }$ and ‘m’ are respectively azimuthal and magnetic quantum numbers.

$\begin{array}{cccc}& \text{Column-I}& & \text{Column-II}\\ \text{(a)}& \text{Number of values of}{}^{\prime }{l}^{\prime }\text{for an energy level}& \text{(p)}& 0,1,\mathrm{2.....}(n-1)\\ \text{(b)}& \text{Actual values of}{}^{\prime }{l}^{\prime }\text{for a particular type of}& \text{(q)}& +‘l^{\prime }\text{to}-‘l^{\prime }\text{through zero}\\ & \text{orbital}& & \\ \text{(c)}& \text{Number of values of 'm' for}{}^{\prime }{l}^{\prime }=2& \text{(r)}& 5\\ \text{(d)}& \text{Actual values of 'm' for a particular type of}& \text{(s)}& n\\ & \text{orbital}& & \end{array}$

• A. $\left(a\right)\to \left(s\right);\left(b\right)\to \left(r\right);\left(c\right)\to \left(q\right);\left(d\right)\to \left(p\right)$
• B. $\left(a\right)\to \left(p\right);\left(b\right)\to \left(s\right);\left(c\right)\to \left(r\right);\left(d\right)\to \left(q\right)$
• C. $\left(a\right)\to \left(s\right);\left(b\right)\to \left(p\right);\left(c\right)\to \left(r\right);\left(d\right)\to \left(q\right)$
• D. $\left(a\right)\to \left(r\right);\left(b\right)\to \left(p\right);\left(c\right)\to \left(q\right);\left(d\right)\to \left(s\right)$

Answer 1

The correct option is C $\left(a\right)\to \left(s\right);\left(b\right)\to \left(p\right);\left(c\right)\to \left(r\right);\left(d\right)\to \left(q\right)$

l = 2 refers to the d orbital, which has 5 sub shells, m value goes from -2 to +2.
The number of ‘l’ values is equal to the principal quantum number.
‘l’ goes from 0 to n-1 where n is the principal quantum number. ‘m’ takes values from -l to +l through zero.