L-shaped rigid lever arm is pivoted at point $P$ . Three forces act on the lever arm as shown in the figure. What is the magnitude of the resultant moment of these forces about point $P$ ?

30 N m

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35 N m

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50 N m

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90 N m

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Solution

The correct option is A $30 N m$

$\begin{matrix} We know that τ = rex F r = perpendiculardist, F = Force * Torgue due to 20 N force will be clockwise τ_{20 N} = 20 N \times 3 m = + 60 N m \end{matrix}$
$\begin{matrix} * torque due to lo N force will be in anticlockwise- τ_{10 N} = 10 N \times 2 m = - 20 N m * Torque due to 5 N foru will be in anticlockwise-_{5 N} = 5 N \times 2 m = - 10 N m \end{matrix}$

$\begin{matrix} Now net torque = Sum of all the torque. \begin{matrix} \Rightarrow τ_{Total} & = τ_{20 N} + τ_{10 N} + L_{S N} = + 60 N m - 20 N m - 10 N m = + 30 N m (clockwise) \end{matrix} Hence, option (A) is correct. \end{matrix}$

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L-shaped rigid lever arm is pivoted at point P. Three forces act on the lever arm as shown in the figure. What is the magnitude of the resultant moment of these forces about point P?

L-shaped rigid lever arm is pivoted at point $P$ . Three forces act on the lever arm as shown in the figure. What is the magnitude of the resultant moment of these forces about point $P$ ?