Question

la3b6 is a five-digit number, where a and bare digits and b exceeds a by 6. If this number is divisible by 18, then $\frac{b}{a}=$

• A. $7$
• B. $3$
• C. $\frac{1}{3}$
• D. $\frac{1}{7}$

Answer 1

Answer: (A)

$7$

Given,
$la3b6$ is a five-digit number,where $a$ and bare digits and $b$ exceeds $a$ by $6$.
$\frac{1+a+3+b+6}{18}$
$=\frac{1+a+3+a+6+6}{18}$
$=\frac{16+2a}{18}$
$\therefore a=1$
$\therefore b=1+6$
$=7$
$\therefore \frac{b}{a}=\frac{7}{1}$
$=7$