Question

Laplace transform of x(t) is $X\left(s\right)=\frac{s-2}{s(s+4)}$ , then the final value of x(t) is _____.

• A. -0.5

Answer 1

The correct option is A -0.5
Given $X\left(s\right)=\frac{s-2}{s(s+4)}$

From final value theorem

$x\left(\infty \right)=\underset{s\to 0}{lim}sX\left(s\right)$

$=\underset{s\to 0}{lim}s.\frac{s-2}{s(s+4)}=\frac{-2}{4}$

$x\left(\infty \right)=\frac{-1}{2}=-0.50$