Largest number of molecules are present in-

44 g m

of carbon dioxide

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28 g m

of carbon monoxide

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36 g m

of water

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64 g m

of sulphur dioxide

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Solution

The correct option is C $36 g m$ of water
$n o . o f m o l e s = \frac{G i v e n m a s s}{M o l a r m a s s} 44 g m {C O}_{2} = 1 m o l e 28 g m C O = 1 m o l e 36 g m H_{2} O = 2 m o l e s 64 g m S O_{2} = 1 m o l e$
Since, number of moles is proportional to the number of molecules, option C will be correct.

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Largest number of molecules are present in-

The correct option is C 36gm of waterno. of moles = Given massMolar mass44gm CO2 = 1 mole28gm CO = 1 mole36gm H2O = 2 moles64gm SO2 = 1 moleSince, number of moles is proportional to the number of molecules, option C will be correct.