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Byju's Answer
Standard XII
Mathematics
Fundamental Laws of Logarithms
Last three di...
Question
Last three digits in
19
100
is
A
001
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B
010
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C
100
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D
999
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Solution
The correct option is
A
001
(
19
)
100
=
(
20
−
1
)
100
=
20
k
+
100
C
98
⋅
20
2
−
100
C
99
20
+
1
=
20
k
+
1980000
−
2000
+
1
=
20
k
+
1978001
since the last tree digits of
20
k
will be zeros so the last three digits of
(
19
)
100
will be same as
1978001
So,
he last three digits of
(
19
)
100
are
001
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