Question

Latent heat of fusion of ice is 333 J/g at $0^{\circ }$ C. Entropy change in entropy units when one mole of ice melts is nearly

• A. 22
• B. 6
• C. -6
• D. -22

Answer 1

The correct option is A 22

Entropy change $\Delta S=\frac{Q}{T}$
Amount of heat absorbed per mole, Q = 333 $\times$ 18 J
Temp = $0^{\circ }$ C = 273 K
$\therefore \Delta S=\frac{333\times 18}{273}=21.95J/K$