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Question

LCM and HCF of (x+1)2 and x3+1


A

HCF = (x1)

LCM = (x+1)(x2x+1)

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B

HCF = (x+1)

LCM = (x+1)(x2x1)

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C

HCF = (x+11)

LCM = (x+1)(x25x+1)

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D

HCF = (x+1)

LCM = (x+1)2(x2x+1)

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Solution

The correct option is D

HCF = (x+1)

LCM = (x+1)2(x2x+1)


First expression (x+1)2=(x+1)(x+1)

Second expression x3+1=(x+1)(x2x+1)

HCF = (x+1)

LCM = (x+1)2(x2x+1)


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