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Byju's Answer
Standard X
Mathematics
Method of Finding LCM
LCM of 23× 3 ...
Question
LCM of (2
3
× 3 × 5) and (2
4
× 5 × 7) is
(a) 40
(b) 560
(c) 1680
(d) 1120
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Solution
(c) 1680
LCM (
2
3
×
3
×
5
,
2
4
×
5
×
7
)
∴ LCM = Product of greatest power of each prime factor involved in the numbers
=
2
4
×
3
×
5
×
7
=
16
×
3
×
5
×
7
= 1680
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Similar questions
Q.
If
a
=
2
3
×
3
2
×
5
and
b
=
2
4
×
3
×
7
2
, then which of the following is true?
Q.
If a =
2
3
×
3
, b =
2
×
3
×
5
, c =
3
n
×
5
and LCM (a, b, c) =
2
3
×
3
2
×
5
, then n = ?
(Here, n is a natural number)
Q.
HCF of (2
3
× 3
2
× 5), (2
2
× 3
3
×5
2
) and (2
4
×
3
× 5
3
× 7) is
(a) 30
(b) 48
(c) 60
(d) 105
Q.
The LCM of
(
x
−
3
)
(
x
−
5
)
a
n
d
(
x
−
5
)
(
x
−
7
)
is:
Q.
Find the LCM of
2
3
4
and
1
4
5
.
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