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Question

LCM of two numbers A and B = Px×Qy, where P and Q are prime numbers and x and y are positive whole numbers. How many sets of values are possible for A and B?

A
xy (x + y)
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B
xy(x - y)
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C
x2y2(x+y)
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D
None of these
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Solution

The correct option is D None of these
Solve this question by substitution.
Let P = 2, Q = 3 and x = y = 1.
Then LCM of two numbers A and B = 6
So the possible set of values for A and B are (1,6); (2,3); (3,2); (6,1) = 4 ways.
None of the options gives 4 on substituting values of x and y.
Hence, option (d) is the correct answer.

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