Question

LCM of two numbers A and B = $P^x\times Q^y,$ where P and Q are prime numbers and x and y are positive whole numbers. How many sets of values are possible for A and B?

• A. xy (x + y)
• B. xy(x - y)
• C. $x^2{y}^2(x+y)$
• D. None of these

Answer 1

The correct option is D None of these

Solve this question by substitution.
Let P = 2, Q = 3 and x = y = 1.
Then LCM of two numbers A and B = 6
So the possible set of values for A and B are (1,6); (2,3); (3,2); (6,1) = 4 ways.
None of the options gives 4 on substituting values of x and y.
Hence, option (d) is the correct answer.