Question

Lead chloride has a solubility product of $1.7\times {10}^{-5}$. What is its solubility in $moles/L$?

Answer 1

Lead Chloride$⟶Ksp=1.7\times {10}^{-5}$

$PbC{l}_2\rightleftharpoons P{b}^{2+}+2C{l}^{-}s2s$

$Ksp=4s^3$

$1.7\times {10}^{-5}=4\times s^3$

$s=0.0161981$