Lead nitrate on strong heating gives :

P b O, N O_{2}, O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P b O_{2}, P b O, N O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P b O, N O, O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P b O, N O, N O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $P b O, N O_{2}, O_{2}$
Strong heating of lead nitrate results in the evolution of a brown gas, nitrogen dioxide, and a yellow residue of lead oxide

$2 P b (N O_{3})_{2} \to 2 P b O + 4 N O_{2} + O_{2}$
So $P b O, N O_{2}, O_{2}$ are obtained.

Suggest Corrections

Similar questions

P b {({N O}_{3})}_{2} ⟶ P b O + {N O}_{2} + O_{2}

P b O_{2}

P b O

O_{2}

M n O_{2} + H C l \to M n C l_{2} + C l_{2} + H_{2} O

N H_{4} C l + C a (O H)_{2} \to N H_{3} + C a C l_{2} + H_{2} O

B a C l_{2} + A l_{2} (S O_{4})_{3} \to B a S O_{4} + A l C l_{3}

N a A l O_{2} + H_{2} O + C O_{2} \to A l H_{3} + N a_{2} C O_{3}

N H_{3} + O_{2} \to N O + H_{2} O

Z n + H N O_{3} \to Z n (N O_{3})_{2} + N O_{2} + H_{2} O

H_{2} S + O_{2} \to H_{2} O + S O_{2}

P b O + C \to P b + C O_{2}

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + H C l

C H_{4} + O_{2} \to C O_{2} + H_{2} O

Balance the following equations

a)Pb(NO₃)₂ gives PbO +NO₂+O₂

b)NH₃+CuO gives Cu+N₂+H₂O

c)NaOH+H₂SO₄ gives Na₂SO₄ +H₂O

d)Al₄C₃+H₂O gives CH₄+Al(OH)₃

Join BYJU'S Learning Program