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Question

Lead sulphide in dilute nitric acid gives :

A
lead nitrate
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B
sulphur trioxide
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C
sulphur dioxide
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D
colloidal sulphur
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Solution

The correct options are
A lead nitrate
D colloidal sulphur
3PbS+8HNO33Pb(NO3)2+3S+2NO+4H2O
When lead sulphide reacts with nitric acid, lead nitrate is formed, along with colloidal sulphur, nitric oxide and water.

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